4351: GESP C++ 四级 4图像压缩202306

内存限制:128 MB 时间限制:1.000 S
评测方式:文本比较 命题人:
提交:1 解决:1

题目描述

样例输入 复制

10
00FFCFAB00FFAC09071B5CCFAB76
00AFCBAB11FFAB09981D34CFAF56
01BFCEAB00FFAC0907F25FCFBA65
10FBCBAB11FFAB09981DF4CFCA67
00FFCBFB00FFAC0907A25CCFFC76
00FFCBAB1CFFCB09FC1AC4CFCF67
01FCCBAB00FFAC0F071A54CFBA65
10EFCBAB11FFAB09981B34CFCF67
01FFCBAB00FFAC0F071054CFAC76
1000CBAB11FFAB0A981B84CFCF66

样例输出 复制

ABCFFF00CB09AC07101198011B6776FC
321032657CD10E
36409205ACC16D
B41032657FD16D
8F409205ACF14D
324F326570D1FE
3240C245FC411D
BF4032687CD16D
8F409205ACC11D
B240326878D16E
83409205ACE11D

提示

#include <iostream>
#include <cstring>
using namespace std;

int image[20][20];
int cpimg[20][20];
int his[256];
int color[16];
// 一位十六进制字符转换为数字
int trans(char a) {
    if (a <= '9')
        return (a - '0');
    return (a - 'A' + 10);
}
// 一位十六进制数字转换为字符
char itrans(int n) {
    if (n >= 10)
        return (char)(n - 10 + 'A');
    return (char)(n + '0');
}
// 寻找离 c 最近的灰阶
int compress(int c) {
    int dis = 256, res = -1;
    for (int i = 0; i < 16; i++) {
        int d = c - color[i];
        if (d < 0)
            d = -d;
        if (d < dis) {
            dis = d;
            res = i;
        }
    }
    return res;
}
int main() {
    int N = 0, M = 0;
    cin >> N;
    // 灰阶计数,初始化为-1
    for (int i = 0; i < 256; i++)
    his[i] = -1;
    // 输入图像,并对灰阶计数
    for (int i = 0; i < N; i++) {
        char line[50];
        cin >> line;
        M = strlen(line) / 2;
        for (int j = 0; j < M; j++) {
            int c = trans(line[j * 2]) * 16 + trans(line[j * 2 + 1]);
            image[i][j] = c;
            his[c]++;
        }
    }
    // 选取出现次数最多的 16 个灰阶
    for (int c = 0; c < 16; c++) {
        int max = 0, max_id = -1;
        for (int i = 0; i < 256; i++)
        if (his[i] > max) {
            max = his[i];
            max_id = i;
        }
        color[c] = max_id;
        his[max_id] = -1;
    }
    // 将 image 的灰阶压缩为 cpimg
    for (int i = 0; i < N; i++)
        for (int j = 0; j < M; j++)
            cpimg[i][j] = compress(image[i][j]);
    // 输出选取的 16 个灰阶
    for (int c = 0; c < 16; c++)
        cout << itrans(color[c] / 16) << itrans(color[c] % 16);
    cout << endl;
    // 输出压缩后的图像
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < M; j++)
            cout << itrans(cpimg[i][j]);
        cout << endl;
    }
    return 0;
}